Question

pH of a saturated solution of Ba(OH)₂ is 12. The value of
solubility product (Kₛₚ)of Ba(OH)₂ is :
(a) 3.3 × 10⁻⁷(b) 5.0 × 10⁻⁷
(c) 4.0 × 10⁻⁶ (d) 5.0 × 10⁻⁶

Answer 1

Answer:

Your answer is option (b)5.0 × 10⁻⁷

Answer 2

Explanation:

pH of a saturated solution of Ba(OH)₂ is 12. The value of

solubility product (Kₛₚ)of Ba(OH)₂ is :

(a) 3.3 × 10⁻⁷(b) 5.0 × 10⁻⁷✔️

(c) 4.0 × 10⁻⁶ (d) 5.0 × 10⁻⁶