Question

ph of a solution is 2 and ph of another solution is 6 then find the net ph of the soultion

Answer 1

You can solve it using normality and volume(N1V+N2V=Nfinal.Vfinal)
The volume is to be known for it. If it isn't given take volume V for both solutions.
The conc. of H+ ions will act as N as for ph=2, N=10^-2.
And the total volume at the end will be 2V.

Answer 2

Answer:

Explanation:

ph of solution 1=2

therefore

h plus = 10^-ph =10^-2

ph os solution 2 = 6

h plus =10^-ph=10^-6

total h plus = 10^-2+10^-6

=10^-6(10^4+1)

=10^-6(10001)

ph=-log h plus

=-log(10^-6(10001)

=-{-6+log 10001}

-{-6+log 1.0001 * 10^4}

-{-6+4+log 1.0001 }

-{-2+log 1.0001 }

-{-2+0.000003 }

-{-1.999997}

1.999997