Question

Ph of solution of h2so4 is 1 assuming complete ionisation find the molarity of h2so4 solution

Answer 1

Answer:For strong acids and strong bases the H+ concentration is equal to Normality why because they undergoes complete dissociation

So,,Ph given is 1,,Then from formula Ph=-log10*H+conc

H+concis10*-1

Explanation:

H+concentration=Normality=0.1

Normality=molarity×n factor

H2so4 nfactor is 2

0.1=molarity×2

0.05is Molarity

I hope you understand well thank you

Answer 2

0.5 M is the molarity of sulfuric acid solution.

Explanation:

The pH of the solution = 1

$pH=-\log[H^+]$

$1=-\log[H^+]$

$[H^+]=10 M$

$H_2SO_4(aq)\rightarrow SO_4^{2-}(aq)+2H^+(aq)$

2 moles of hydrogen ions are obviated from the 1 mole of sulfuric acid .

Then 1 mol/L of hydrogen ions will be given by:

$\frac{1}{2}\times 1 M=0.5 M$

0.5 M is the molarity of sulfuric acid solution.

Learn more about molarity:

https://brainly.com/question/13799132

https://brainly.com/question/3797556