Question

pH + poh = 14 prove that ​

Answer 1

Explanation:

PH may be defined as negative logarithm of hydrogen ion concentration

for hydrogen ion

${oh}^{ - }$

$( {oh}^{ - } ) = {10}^{ - poh } \\ log(oh) = poh log_{10} \\ {p}^{oh = - log( {oh}^{ - } ) } \\ ( {h}^{ + } )( {oh}^{ - } ) = kw = {10}^{ - 14} \\ log( {h}^{ + } ) + log( {oh}^{ - } ) = log(kw) = log_{10}( {10}^{ - 14} ) \\ - ph - poh = - 14 \\ ph + poh = 14$

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Answer 2

Answer in attachment!

Explanation:

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