Question

Ph values of HCL and NaOH solutions each at strength N/100 will be

Answer 1

Answer:

for HCl pH = 2

for NaOH pH = 12

Explanation:

Given

Normality = N/100

pH = ??

Solution

N/100 = 0.01 N HCl

therefore

[H⁺] = 10⁻² M

pH = - log [H⁺]

pH = 2

For NaOH

[OH⁻] = 10⁻² M

pOH = 2

pH + pOH = 14

pH = 14 - 2

pH = 12