Phase difference between voltage across L and C in series is
Answers
Answer:
The magnitude of the Voltage drops will depend on the reactance of each component (which are themselves frequency dependent)
Xl = 2 Pi f L and Xc = 1 / (2 Pi f C)
The phase relationships will depend on the resistive element of the coil, and to a lesser extent the “quality” of the capacitor’s dielectric.
The two Voltage drops will “add” to the supply Voltage, BUT, this would be a phasor addition; Vs = Root (Vl^2 + Vc^2)
If “pure” components were possible, the two Voltage drops would be 180 degrees out of phase with one another (Voltage leading the current by 90 degrees in the coil, and lagging the current by 90 degrees in the capacitor)
Capacitors are “reasonably “ pure, so to try and answer your question, I’d approximate and say….. the two Voltage drops would be out of phase with one another by more than 90 degrees, but less than 180 degrees.
You may like to read up on AC resonance.
Explanation: