Question

Phase space, of a particle falling freely under gravity from a height, starting from rest

Answer 1

h=[1/2]gt^2 = 25[4.9]

2h = 4.9t^2 = 50[4.9]

t=5 sq rt 2 = time to fall 2h

time difference between2h and h =dt = 5 rt2 -5 = 5[1.414–5] = 2.07 secs

Answer 2

Answer:

The answer is 2.07 seconds.....