Question

Phenol associates in benzene to form a dimer (c6h5oh)2. the freezing point of the solution containing 5g of phenol in 250g of benzene is lowered by 0.70°c. calculate the degree of association of phenol in benzene (k for benzene = 5.12km^-1)

Answer 1

Answer:

degree of association is 71.6 %

Explanation:

The chemical reaction given in question statement can be written as;

2C6​H5​OH ⇌ (C6​H5​OH)2​

Total=1− α + α/2

1−α/2

Now Van't Hoff factor  for association would be

I = [1−(α/2)] /1 =

I = 1− α/2

ΔTf = I Kf W2 ×1000Mw2×W1

0.7 = ( i×5120×5g) / (94×250g )

I = 0.642

I = 1−α/2,

Α = 0.716

   =71.6 %

Hence degree of association is 71.6 %

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