Math, asked by Kaitlynle07, 5 months ago

Phillip is an avid video game player and movie watcher.He has a choice of belonging to a video ],[ club with a monthly fee of $12 and a $1 a day rental fee for any movie or game or he can be a ],[ nonmember and pay a $2.50 a day rental fee for any movie or game.Which of the following is a ],[ reasonable solution for the number of movies or video games Phillip must rent for the cost to be ],[ equal between membership and non-membership?

Answers

Answered by shlokatomar
1

Answer:

8 video games/movies a month

Step-by-step explanation:

Taking the number of video games/movies he rents to be x,

12 + 30x = 2.5 * 30 * x     (This is the equation for his monthly cost)

30x + 12 = 75x

45x = 12

x = 12/45 = 4/15 = 4 movies in 15 days or 8 movies in a month.

Hence, he must rent 8 movies/video games a month for the cost to be equal between membership and non-membership.

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