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Out of a certain sum of money a boy spends 3/5,and then 1/4 of the remainder.He has rupees 15 left.How much amount had he at first?
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1
Answer:
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Answered by
1
Answer:
At first he had 50 rupees.
Step-by-step explanation:
Let boy has x amount of money.
Amount spent = 3/5x
Amount remaining = x - 3/5x
= 2/5x
Then he spent 1/4 amount of money , so
Amount spent 2nd time = 1/4 × 2/5x
= 1/10x
Amount remain = 2/5x - 1/10x
= 3/10x
He was left with 15 rupees .
thus,
3/10x = 15
3x = 150
x = 150/3
x = 50
Therefore he was left with the amount of 50 rupees.
hope it will help u !
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