Question

Photoelectric work function for a surface is 2.4 eV. Light of wavelength 6.8 x10-7 m shines on the surface. Find the frequency of incident light and also the threshold frequency. Will there be photoelectric emission or not?

Answer 1

Answer:

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Explanation:

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Answer 2

0.44 × 10 ( power 15 ) Hz

Explanation:

W = 2.4 ev

W = Hvo

Vo = W upon H

Vo = 2.4 × 1.6 × 10 ( power minus 19 )

6.626 × 10 × ( power minus 34 )

Vo = 0.57 × 10 ( power 15) Hz

^ = 6.8 × 10 ( power 15 ) Hz

^u = C

V = C

H

= 3 × 10 ( power 8 )

6.8 × 10

V = 0.44 × 10 ( power 15 ) Hz

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