php coding to display name age address
Answers
<!DOCTYPE html>
<html>
<head>
<title></title>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
</head>
<body>
<form method='POST'>
<h2>Please input your name:</h2>
<input type="text" name="name">
<input type="submit" value="Submit Name">
</form>
<?php
//Retrieve name from query string and store to a local variable
$name = $_POST['name'];
echo "<h3> Hello $name </h3>";
?>
</body>
</html>
tq
Answer:
- Using echo command, we can display name, age and address.
<html>
<head>
<title>Employee Detail</title>
</head>
<body>
<?php
$name = "Amit";
$age = 23;
$address = "India";
echo "Employee name is".$name;
echo "Employee is ".$age."years old";
echo "He lives in the".$address;
<?
</body>
</html>
2. Using Print command, we can display name, age and address.
<html>
<head>
<title>Employee Detail</title>
</head>
<body>
<?php
$name = "Amaan";
$age = 25;
$address = "United States";
print "Employee name is".$name;
print "<br>";
print "He is".$age."years old";
print "<br>";
print "He lives in the".$address;
<?
</body>
</html>
Explanation:
- echo and print are used to output data to the screen.
- echo has no return value while print has a return value of 1.
- echo can take multiple arguments but print can take only one argument.
- echo is little faster than print.