Question

Physics



1. The voltage across a 1000 μf capacitor falls linearly from 5.0 v to 1.0 v in 10 ms. What is the current in the leads of the capacitor during this process?

Answer 1

In terms of voltage, this is because voltage across the capacitor is given by Vc = Q/C, where Q is the amount of charge stored on each plate and C is the capacitance. This voltage opposes the battery, growing from zero to the maximum emf when fully charged.