Question

PHYSICS
46. Bulb 'P' marked as 100 W, 220 V and bulb Q
marked as 60 W, 110 V. The resistance ratio of
P and Q is​

Answer 1

P, r=v^2/p

r=(220*220)/100

r=484 ohm

Q, R=(110*110)/60

R=201.67 ohm

P/Q= r/R

=2.4

P:Q =r:R = 2.4 : 1

Answer 2

Please refer to the picture for the answer.....

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