Physics, asked by sadatahmed607, 10 months ago

(physics)

A damped harmonic oscillator consists of a block (m = 1.50 kg), a spring (k = 10.0 N/m),
and a damping force (F = -bv). Initially, it oscillates with an amplitude of 25.0 cm; because of
the damping, the amplitude falls to three-fourths of this initial value at the completion of four
oscillations. (a) What is the value of b? (b) How much energy has been “lost” during these four
oscillations? (c) Write down the condition to be a simple harmonic oscillator.

Answers

Answered by AdityaBasak
1

Answer:

I don't know sorry .........

Answered by skailashkumar079
0

Answer:

A simple harmonic oscillator of a block of mass 2.00 kg attached to a spring of spring constant 100M/n when t= 1.00s'the

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