Physics Ch MOTION Class 9th pg 109. Plz answer asap!!
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Explanation:
(a) Given, the bust starts from rest. Therefore, initial velocity (u) = 0 m/s
Acceleration (a) = 0.1 m.s-2
Time = 2 minutes = 120 s
Acceleration is given by the equation
Therefore, terminal velocity (v) =
= (0.1 m.s-2 * 120s) + 0 m.s-1
= 12m.s-1 + 0 m.s-1
Therefore, terminal velocity (v) = 12m/s
(b) As per the third motion equation,
Since a = 0.1 m.s-2, v = 12 m.s-1, u = 0 m.s-1, and t = 120s, the following value for s (distance) can be obtained.
Distance, s =
=
Therefore, s = 720m.
The speed acquired is 12m.s-1 and the total distance traveled is 720m.
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