Physics, asked by tanushka71, 9 months ago

Physics Ch MOTION Class 9th pg 109. Plz answer asap!!​

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Answered by Anonymous
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Explanation:

(a) Given, the bust starts from rest. Therefore, initial velocity (u) = 0 m/s

Acceleration (a) = 0.1 m.s-2

Time = 2 minutes = 120 s

Acceleration is given by the equation

Therefore, terminal velocity (v) =

= (0.1 m.s-2 * 120s) + 0 m.s-1

= 12m.s-1 + 0 m.s-1

Therefore, terminal velocity (v) = 12m/s

(b) As per the third motion equation,

Since a = 0.1 m.s-2, v = 12 m.s-1, u = 0 m.s-1, and t = 120s, the following value for s (distance) can be obtained.

Distance, s =

=

Therefore, s = 720m.

The speed acquired is 12m.s-1 and the total distance traveled is 720m.

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