PHYSICS CLASS 10
A conductor of length ‘l’ has resistance 20 Ω.If the length is increased by 4 times, what will be the new resistance? Assume all other parameters, remain connected
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Answer:
320 ohm
Explanation:
as volume remains same
a1l1=a2l2
a l= a"4l
a"= a/4
r"= 4l\a"
=4l/(a/4)
=16r
=16*20
= 320
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