physics ....Class 10
solve it plsss
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First find resistance of the bridge.
1/(1.5+1.5)+1/(1.5+1.5)=2/3=1/Equivalent resistance of bridge.
Req=3/2=1.5ohms.
Total resistance=2+1.5=3.5ohms.
The potential difference remains constant in a circuit.
Hence the potential difference is 9V.
1/(1.5+1.5)+1/(1.5+1.5)=2/3=1/Equivalent resistance of bridge.
Req=3/2=1.5ohms.
Total resistance=2+1.5=3.5ohms.
The potential difference remains constant in a circuit.
Hence the potential difference is 9V.
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