Physics, asked by Ammulushanmukhi123, 1 year ago

physics equation in motion

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Answered by jaria4242
0
s=ut + 1/2at²
10=0×t+1/2×5×t²
10×2÷5=t²
4=t²
√4=t
2s=t
v=u+at
v=0+5×2
v=10m/s
Answered by nandanamohan06
1

Answer:

Explanation:

draw a velocity time graph for a body moving with uniform acceleration.

1. a = v - u/ t

v - u/ t = a

at = v - u

at + u = v

v = u + at

 position - time relation

for that find the area of the graph

we will get

s = 1/2 x t x (v-u) + ut

substituting (v-u) as at

from, a = v - u / t

at = v - u

since  s = 1/2 x t x at x ut

s = 1/2 at² + ut

position - velocity relation

find the area

1/2 x t (u + v )

substituting for t = v-u / a

from , a =v - u/ t

t = v - u / a

since

s = 1/2 (v - u /a) (u + v )

s= 1 / 2a ( v - u ) ( v + u)

s = 1 / 2a (v² - u²)

2as = v² - u²

hope it helps.....

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