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An insect moves along the sides of a wall of dimensions 12m x 5m starting from one corner and reaches the diagonally opposite corner. If the insect takes 2s for its motion, find the ratio of average speed to average velocity. ​

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Answered by Anonymous
16

\huge{\boxed{\red{\it{Answer}}}}

Average speed = Total distance/Total time taken

= Hypotenuse/2s

h {}^{2} = 12 {}^{2} + 5 {}^{2}  \\  \:  \:  \:  \:  \:  \:  = 144 + 25 \\  \:  \:  \:  \:  \:  \:  = 169  \\  \:  \:  \:  \:  \:  \:  = 13 {}^{2}  \\  \:  \:  \:  h = 13

So, Average speed = distance/time

= 17/2 m/s.

Average velocity = displacement/time

= 13/2 m/s.

So, ratio will be => 17:13.

\huge{\boxed{\sf{Answer=17:13}}}

Answered by TheBrainlyAlex
0

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