Question

Physics ❤

How much positive and negative charge is there in a cup ?

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Answer 1

$\large{\underline{\textbf{\red{Question:}}}}$

How much positive and negative charge is there in a cup of water?

$\large{\underline{\underline{\textbf{\green{ANSWER:}}}}}$

Suppose the the mass of water contained in a cup is 250 g. The molecular mass of water is 18 g.

Number of molecules present in 18 g of water

= Avogadro's number = 6.02 × 10²³

$\therefore$ Number of molecules present in a cup (or 250 g) of water

$\implies$ $n = \frac{6.02 \times {10}^{23}\times 250 }{18} = 8.36 \times {10}^{24}$

Each molecule molecule of water ( ${H}_{2}{O}$ ) contains 2 + 8 = 10 electrons as well as 10 protons.

Total number of electrons or protons present in a cup of water,

n' = n × 10 = 8.36 × ${10}^{25}$

Tot negative charge carried by electrons or total positive charge carried by protons in a cup of water,

q = n'e

= 8.36 × ${10}^{25}$ × 1.6 × ${10}^{-19}$ C

= 1.33 × ${10}^{</strong><strong>7</strong><strong>}$ C

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Answer 2

Answer:

Suppose the the mass of water contained in a cup is 250 g. The molecular mass of water is 18 g.

Number of molecules present in 18 g of water

= Avogadro's number = 6.02 × 10²³

\therefore∴ Number of molecules present in a cup (or 250 g) of water

\implies⟹ n = \frac{6.02 \times {10}^{23}\times 250 }{18} = 8.36 \times {10}^{24}n=

18

6.02×10

23

×250

=8.36×10

24

Each molecule molecule of water ( {H}_{2}{O}H

2

O ) contains 2 + 8 = 10 electrons as well as 10 protons.

Total number of electrons or protons present in a cup of water,

n' = n × 10 = 8.36 × {10}^{25}10

25

Tot negative charge carried by electrons or total positive charge carried by protons in a cup of water,

q = n'e

= 8.36 × {10}^{25}10

25

× 1.6 × {10}^{-19}10

−19

C

= 1.33 × {10}^{7}10

7

C

__________________________

Explanation:

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