physics question for class 9 and this question is for 2 marks
please ask fast as it is urgent.......
Attachments:
Answers
Answered by
1
Mass(m)=50 kg,acceleration due to gravity(g)=10 m/s²
Let the distance between A to B be h
At position A,
Gravitational P.E=mgh=50×10×h=500 h
At position B,
Gravitational P.E=mgh=mg(0)=0 (h=0 since the skier has reached the bottom most position)
Change in gravitational P.E from A to B=500 h-0=500 h(Ans.),where h is the distance of A to B.
Let the distance between A to B be h
At position A,
Gravitational P.E=mgh=50×10×h=500 h
At position B,
Gravitational P.E=mgh=mg(0)=0 (h=0 since the skier has reached the bottom most position)
Change in gravitational P.E from A to B=500 h-0=500 h(Ans.),where h is the distance of A to B.
Similar questions