Question

physics question

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A 45N object is lifted to a height of 4 metre. What is the gravitational potential energy of this object?​

Answer 1

Answer:

Here,

F = 45 N

H = 4 m

We know that, g = 9.8 m/s²

Then, F = mg

45 = m×9.8

m = 4.6kg (approx.)

So, P.E. = mgh

= 4.6 × 9.8 × 4

= 180.32 J

Hope it helps buddy

Answer 2

$\boxed{\rm{\blue{Given\longrightarrow }}}$

• Force= 45 N
• Height = 4m

$\boxed{\rm{\red{Find \longrightarrow }}}$

• gravitational potential energy of this object?

$\boxed{\rm{\pink{Formula \ used \longrightarrow }}}$

$\sf{\red{ PE_G= mg \Delta h}}$

where,

• $\sf{PE_G}$ =potential energy due to gravity
• g=acceleration due to gravity
• m=mass
• $\sf{\Delta h}$ = distance above a surface

$\boxed{\rm{\purple{SoLution \longrightarrow }}}$

we know

F= m a here, {a= g}

so the value of mg= F

by Putting  value in the formula we get,

$\sf{PE_G= 45 \times 4}$

$\sf{ PE_G= 180}$

$\underline{\bf{\therefore Gravitational \ Potential \ energy \ = 180 kg m^2 /s^2}}$

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