Question

Subtract 0.8xy-10xyand2xy​

Answer 1

Answer:

Hey mate plzz refer to the attachment

Answer 2

Answer:

Value \: of \: x = 0.6\\and\\y=0.2

Step-by-step explanation:

Given \\\frac{x}{2}+y=0.8 \\\implies \frac{x}{2}=0.8-y---(1)

\frac{7}{\frac{x+y}{2}}=10

\implies 7=10\left(\frac{x+y}{2}\right)

\implies 7=10\left(\frac{x}{2}+\frac{y}{2}\right)

\implies 7=10\left(0.8-y+\frac{y}{2}\right)\:[From\:(1)]

\implies 7 = 10\times 0.8-10y+10\times \frac{y}{2}

\implies 7=8-10y+5y

\implies 7-8=-5y

\implies -1=-5y

\implies y = \frac{1}{5}=0.2--(2)

Substitute \: y = 0.2\: in \\ equation (1)\:we\:get

\frac{x}{2}=0.8-0.2\\=0.6

Therefore,

Value \: of \: x = 0.6\\and\\y=0.2

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refer this