Physics, asked by chandraleka783, 5 hours ago

Physics Question Please answer this fast ​

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Answered by vipinkumar212003
1

let,  mass \: of \: object(m_o) = m\: kg \\ mass \: of \: earth(m_e) = 6 \times {10}^{24}  \: kg \\ mass \: of \: moon(m_{m}) = 7.3 \times  {10}^{22}  \: kg \\ ball \: reaches \: height \: when\: thrown  \\  from \: earth \\  = h_1 \: m \\ball  \: reaches \: height \: when \: thrown  \\  from \: moon\\  = h_2 \: m\\ F_g =  \frac{Gm_om_e}{h_1}  - (i) \\ F_g =  \frac{Gm_om_m}{h_2}  - (ii) \\ \blue{\mathfrak{\underline{\large{by \:  {eq}^{n}  \: (i) \: and \: (ii)}}}:} \\ \frac{Gm_om_e}{h_1} = \frac{Gm_om_m}{h_2} \\ \\  \frac{m_e}{h_1} = \frac{m_m}{h_2} \\  \\  \frac{h_1}{h_2}  =  \frac{m_e}{m_m}  =  \frac{6 \times  {10}^{24} }{7.3 \times  {10}^{22} }  \\  \\   \boxed{\frac{h_1}{h_2}  ≈ 0.82 \times  {10}^{2}  ≈ 82 \: m} \\  \\ \red{\mathfrak{ \large{\underline{{Hope \: It \: Helps \: You}}}}} \\ \blue{\mathfrak{ \large{\underline{{Mark \: Me \: Brainliest}}}}}

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