Question

Physics.
Topic :— Resistance and Resistors​

Answer 1

Answer:

$\sf\large\underline\purple{AnSwEr}$

The equivalent resistance of each parallel branch

$Rₑq1= \frac{R R }{R + R} = \frac{R}{2}$

Now

$Rₑq2 = ( \frac{ (\frac{R}{2})( \frac{R}{2} +R + \frac{R}{2} ) }{ (\frac{R}{2}) + ( \frac{R}{2} +R + \frac{R}{2})} )$

→$\frac{( \frac{R}{2} )(2R)}{(\frac{R}{2} ) + (2R)} = \frac{2R}{5}$

$Rₑq3 = \frac{R}{2} + \frac{2R}{5} + \frac{R}{2} = \frac{7R}{5}$

Thus,

$Rₐₑ = \frac{R( \frac{7R}{5}) }{R + \frac{7R}{5} } = \frac{7}{12} R$