Question

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Answer 1

ANSWER

Let cross sectional area of tube=A

length of tube=L

for equilibrium,

weight of tubeW

T

= buoyancy force by water

So,

W

T

= ρ

w

gA×5

after pouring liquid,

Wt = ρ

w

gA×5

after pouring liquid,

W

T

=ρ

w

gA×8=ρ

w

gA×9

ρ

w

gA⋅5=ρ

w

gA⋅8=ρ

w

gA⋅9

⇒ρ

l

=

2

ρ

w

.