Question

Please fill in the missing lines of code to complete the following menu driven C program to
implement a calculator.
Logic:
.
1- Accept two numbers x and y as input.
- Accept a value as choice.
• - If the choice is 1, add the two numbers and store x+y in the variable result
. - If the choice is 2, subtract the two numbers and store x-y in the variable result
• - If the choice is 3, multiply the two numbers and store x*y in the variable result
• - If the choice is 4, divide the two numbers and store x/y in the variable result.



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Answer 1

Explanation:

swPlease fill in the missing lines of code to complete the following menu driven C program to implement a calculator.

Logic:

- Accept two numbers x and y as input.

- Accept a value as choice.

- If the choice is 1, add the two numbers and store x+y in the variable result

- If the choice is 2, subtract the two numbers and store x-y in the variable result

- If the choice is 3, multiply the two numbers and store x*y in the variable result

- If the choice is 4, divide the two numbers and store x/y in the variable result

Answer 2

Answer:

Explanation:

Implementing a calculator :

Logic:

1- Accept two numbers x and y as input.

- Accept a value as choice.

• - If the choice is 1, add the two numbers and store x+y in the variable result

. - If the choice is 2, subtract the two numbers and store x-y in the variable result

• - If the choice is 3, multiply the two numbers and store x*y in the variable result

• - If the choice is 4, divide the two numbers and store x/y in the variable result.

Program to implement a calculator :

#include <stdio.h>

int main() {

int x, y;

int choice;

printf("Enter 1. for "+", 2. for "-", 3. for "*", 4. for "/" ");

scanf("%c", &choice);

printf("Enter two operands: ");

scanf("%d %d", &x, &y);

 switch (choice) {

   case '1' :

     printf("%d + %d = %d", x, y, x + y);

     break;

   case '-':

     printf("%d - %d = %d", x , y, x - y);

     break;

   case '*':

     printf("%d * %d = %d", x, y, x * y);

     break;

   case '/':

     printf("%d / %d = %d", x, y, x/y);

     break;

   default:

     printf("Error, operator is not correct");

 }

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