Question

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Answer 1

Answer:

Maximum torque on the dipole = 2 x 10⁻² N m

Explanation:

Electric Field E = 10⁵ NC⁻¹

Magnitude of charge q = 10μC = 10⁻⁵ C

dipole length 2a = 2 cm = 2 x 10⁻² m

Magnitude of torque τ = p E sinθ

Maximum torque τ = p E

                                = q x 2a x E

                                = 10⁻⁵ x 2 x 10⁻² x10⁵

                                = 2 x 10⁻² N m

The direction of torque is perpendicular to both vectors p and E

Magnitude of torque =