Question

piece of iron of density 156g and 7.8g/cm3 floats on mercury of density 13.6g/cm3. what id the minimum force required to submerge it
please answer fast​

Answer 1

Answer:

116gf

Explanation:

Solution

Step 1: Given data,

Density of iron = 7.8g/cm3

Mass of iron = 156g

So, weight of iron will be = 156gf

Density of mercury = 13.6g/cm3

Step 2: Finding the minimum force required to submerge the iron,

To submerge the iron, the relative density has to be increased from 7.8g/cm3 to 13.6g/cm3

Applying unitary method;

If density is 7.8g/cm3 the mass is = 156g

If the density is 1kg/m3 the mass will be = 156g7.8g/cm3

Therefore, If the density is 13.6g/cm3 the mass will be = 156g7.8g/cm3×13.6g/cm3=272g

Hence, the weight should be 272gf

So the external minimum force required to submerge the iron is 272gf-156gf=116gf