Question

piece of metal pipe aap is 35 cm long the inner diameter of cross section is 14cm and Outer diameter is 16 cm if the weight of metal is 10 gm per cm what is the weight of the piece of pipe​

Answer 1

Step-by-step explanation:

GIVEN:-

HEIGHT OF THE PIPE = 35 CM

INNER DIAMETER = 14 CM

OUTER DIAMETER = 16 CM

TO FIND:-

WEIGHT OF THE PIECE OF PIPE

FINDING:-

INNER RADIUS = 7 CM

OUTER RADIUS = 8CM

ANALYSIS:-

SINCE TEG PIPE IS IN THE FORM OF CYLINDER,

VOLUME OF CYLINDER = πr^2h

SOLUTION:-

$volume \: of \: pipe \: with \: inner \: radius = \frac{22}{7} \times 7 \times 7 \times 35 \\ = 22 \times 49 \times 5 \\ = 5390 \: cm {2}$

$volume \: of \: pipe \: with \: outer \: radius = \frac{22}{7} \times 8 \times 8 \times 35 \\ = 22 \times 64 \times 5 \\ = 7040 \: cm {2}$

SO, THE VOLUME OF METAL USED = VOLUME OF PIPE WITH OUTER RADIUS - VOLUME OF PIPE WITH INNER RADIUS.

= 7040 - 5390

= 1650

NOW , WEIGHT OF 1650^3 METAL IS 10gms PER CM^3.

SO, WEIGHT OF 1650^3 CM METAL= 1650 × 10

HENCE THE WEIGHT OF PIECE IF PIPE IS 16.500 KG

Answer 2

Answer:

weight = 16.500KG

Step-by-step explanation:

Hope this helps mate