Physics, asked by aniket5712, 5 hours ago

Pinky exerts a power of 50 W and does work for 1 hour. Sweety exerts a power of 80 W
but does work for half hour. Who has done more work, Pinky or Sweety?

Answers

Answered by dankstars585
5

Answer:

Pinky

Explanation:

work done = power*time

work done by pinky= 50W* (60*60) seconds

=50*3600= 180000joules

similarly

work done by sweety = 80W*(30*60) seconds

=80*1800 = 14400joules

hence pinky has done more work

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