Question

Pinky runs 8 time around a rectangular Park with length 80 and breadth 55 m while Pankaj runs 7 time around a square Park of side 75 m .who cover more distance and by how much

Answer 1

Length of the park Pinky ran in = 80m

Breadth of the park Pinky ran in = 55m

Therefore, perimeter of the park Pinky ran in
= [2(80+55)] m
= 2×135
= 270

Therefore, total distance covered by Pinky = (270×8)m
=2160m

Sides of the park Pankaj ran in
=75m

Therefore, perimeter of the park Pankaj ran in = (75×4)m
=300m

Therefore total distance covered by Pankaj = 300×7
=2100m

Since 2160>2100, Pinky ran more distance, and by: (2160-2100)m = 60m. Answer- Pinky covered more distance by 60m.

Answer 2

Solution :

Length of the rectangular park = 80m

Breadth of the rectangular park = 55m

.°. Perimeter of the rectangular park

= [2 (80 + 55)]

= 2 × 135

= 270m

.°. Total distance covered by Pinky

= 270 × 8

= 2160m

.°. Sides of the square park = 75m

.°. Perimeter of square park

= 4 × side

= 4 × 75

= 300m

.°. Total distance covered by Pankaj

= 300 × 7

= 2100m

Therefore, Pinky cover more distance by 60m.