Pipe a and b running together can fill a cistern in 6 minutes. If b takes 5 minutes more than a to fill the cistern, then the time in a and b will fill the cistern separately what time?
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Hey Dear,
◆ Answer -
A => 10 min
B => 15 min
◆ Explaination -
Let x and y be time taken by A and B to fill cistern independently.
According to given data, we can form equations -
6 (1/x + 1/y) = 1 ...(1)
y = x + 5 ...(2)
So putting eqn (2) in eqn (1) will be,
6 (x+y) / xy = 1
6 (x+x+5) = x (x+5)
12x + 30 = x² + 5x
x² - 7x - 30 = 0 ...(3)
Solving this eqn (3),
x = 10 min
y = x+5 = 10+5 = 15 min
Therefore, A can fill cistern in 10 min and B can fill the same in 15 min independently.
Thanks dear...
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