Math, asked by Abadra, 5 hours ago

Pipe A can fill 3/4th of a tank in 6 hours. Pipe B can fill 2/3rd of the tank in 8 hours. If both pipes are used together, how long will they take to fill the full tank?
please help me

Answers

Answered by anusujasree
0

Answer:

Solution

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Correct option is

C

14

Part time in 2 hours=

6

2

=

3

1

Remaining part=(1−

3

1

)=

3

2

.

∴(A+B)'s 7 hour's work=

3

2

(A+B)'s 1 hour's work=

21

2

∴ C's hour's work={(A+B+C)'s 1 hour's work}−{(A+B)'s 1 hour's work}

=(

6

1

21

2

)=

14

1

∴ C alone can fill the tank in 14 hours.

Step-by-step explanation:

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