Pipe A can fill 3/4th of a tank in 6 hours. Pipe B can fill 2/3rd of the tank in 8 hours. If both pipes are used together, how long will they take to fill the full tank?
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Correct option is
C
14
Part time in 2 hours=
6
2
=
3
1
Remaining part=(1−
3
1
)=
3
2
.
∴(A+B)'s 7 hour's work=
3
2
(A+B)'s 1 hour's work=
21
2
∴ C's hour's work={(A+B+C)'s 1 hour's work}−{(A+B)'s 1 hour's work}
=(
6
1
−
21
2
)=
14
1
∴ C alone can fill the tank in 14 hours.
Step-by-step explanation:
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