Question

Pipe a can fill a tank in 18 hours, pipe b can empty a tank in 12 hours, pipe c can fill tank in 6 hours. The tank is already filled up to 1/6 of its capacity. Now pipe a is opened in the first hour alone, pipe b is opened in the second hour alone and pipe c is opened in the third hour alone. This cycle is repeated until the tank gets filled. Then in how many hours does the rest of tank gets filled

Answer 1

Answer: The Rest of the tank gets filled in 18 Hours.

In First Hour Tank filled = 1/6+1/18

Second Hour = 1/6+1/18-1/12

Third Hour = 1/6+1/18-1/12+1/6 = 11/36 is filled

25/36 is left

From then 3 hours work = 1/18-1/12+1/6 = 5/36

5*3 Hours = 5*5/36 = 25/36

Total = (5*3)+3 = 18 Hours.

Hope it helps you....

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