Pipe A can fill a Tank in 18 Hours, Pipe B can empty a Tank in 12 Hours, Pipe C can fill Tank in 6 Hours. The Tank is already filled up to 1/6 of its capacity. Now Pipe A is opened in the First Hour alone, Pipe B is opened in the Second Hour alone and Pipe C is opened in the Third Hour alone. This cycle is repeated until the Tank gets filled. Then in How many Hours does the rest of Tank gets filled?
A. 15 Hours
B. 18 Hours
C. 20 Hours
D. 24 Hours
Answers
Answered by
1
Answer – B. 18 Hours
Explanation :
In First Hour Tank filled = 1/6+1/18
Second Hour = 1/6+1/18-1/12
Third Hour = 1/6+1/18-1/12+1/6 = 11/36 is filled
25/36 is left
From then 3 hours work = 1/18-1/12+1/6 = 5/36
5*3 Hours = 5*5/36 = 25/36
Total = 5*3+3 = 18 Hours.
hope it helps you
Explanation :
In First Hour Tank filled = 1/6+1/18
Second Hour = 1/6+1/18-1/12
Third Hour = 1/6+1/18-1/12+1/6 = 11/36 is filled
25/36 is left
From then 3 hours work = 1/18-1/12+1/6 = 5/36
5*3 Hours = 5*5/36 = 25/36
Total = 5*3+3 = 18 Hours.
hope it helps you
pala3377:
hi
Answered by
2
Answer:
Step-by-step explanation:
Left part 1-1/6= 5/6
3 hours work 1/18-1/12+1/6=5/36
5/36 potion filled in 3 hour
1 potion fill in 36*3/5 hour
5/6 portion fill in 36*5*3/5*6= 18 hours
Answer: 18 hours
Razibur rahman
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