Question

pipe A can fill a tank in 6 minutes while pipe b alone can fill it in 10 minutes and pipe c can empty the full tank in 15 minutes.if all the pipes are opened together how much time will be needed to make a tank full​

Answer 1

Step-by-step explanation:

efficiency pipe. time total

+5 A. 6m.

+ 3 B. 10m. } 30.

- 2 C. 15m

___________

= 6

time = work/ efficiency

= 30/6

= 5 minutes. (answer)

Answer 2

If all the pipes are opened together, the tank gets filled in 5 minutes

Solution:

Given that,

Pipe A can fill a tank in 6 minutes

Therefore,

Pipe A fills $\frac{1}{6}$ of the tank in 1 minute

Pipe B alone can fill it in 10 minutes

Therefore,

Pipe B fills $\frac{1}{10}$ of the tank in 1 minute

Pipe C can empty the full tank in 15 minutes

Therefore,

Pipe C empties $\frac{1}{15}$ of the tank in 1 minute

If all the pipes are opened together how much time will be needed to make a tank full​

$\rightarrow \frac{1}{6} + \frac{1}{10} - \frac{1}{15}\\\\\rightarrow \frac{1 \times 5}{6 \times 5} + \frac{1 \times 3}{10 \times 3} - \frac{1 \times 2}{15 \times 2}\\\\\rightarrow \frac{5}{30} + \frac{3}{30} - \frac{2}{30}\\\\\rightarrow \frac{5 + 3 - 2}{30}\\\\\rightarrow \frac{6}{30} = \frac{1}{5}$

Thus, if all the pipes are opened together, the tank gets filled in 5 minutes

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