Question

Pipe a can fill the tank in 8 hours and pipe b can fill it in 12 hours. If pipe a is opened at 7:00 am and pipe b is opened at 9:00 am, then at what time will the tank be full?

Answer 1

Please see the attachment

Answer 2

The tank will be full at 12:36 p.m.

Step-by-step explanation:

Pipe a can fill the tank in 8 hours

Pipe A 1 hour work =$\frac{1}{8}$

Pipe b can fill it in 12 hours

Pipe B 1 hour work =$\frac{1}{12}$

Pipe A and pipe B together can do part of work in 1 hour = $\frac{1}{8}+\frac{1}{12}=\frac{3+2}{24}=\frac{5}{24}$

pipe a is opened at 7:00 am and pipe b is opened at 9:00 am

9 a.m. - 7 a.m. = 2 hours

So, Pipe A 2 hours =$\frac{2}{8}$

So, remaining work = $1-\frac{2}{8}=\frac{6}{8}$

Pipe A and B can do$\frac{5}{24}$work in hours = 1

Pipe A and B can do$\frac{6}{8}$work in hours = $\frac{\frac{6}{8}}{\frac{5}{24}}=3.6 hours$

So, 9 a.m.+3.6 hours = 12:36 p.m.

Hence the tank will be full at 12:36 p.m.

#Learn more:

Tap A and Tap B are fitted to a tank. Tap A can fill an empty tank in 8 hours and tap B

can empty the full tank in 3 hours. If both the taps are opened at 6:00 a.m., then by

what time will the full tank be emptied?​

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