Math, asked by harjitkaurbti7, 6 months ago

Pipe A takes 24 minute to fill a tank. Pipe B takes 32 minutes to fill the same
tank. If both the pipes are opened simultaneously, after how much time should
pipe A be closed so that it takes 16 minute to fill the tank.
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Answers

Answered by Anonymous
8

Step-by-step explanation:

Let the total capacity of the tank be 96 units (LCM of 24 & 32).

A fills =

24

96

= 4 units / minute.

B fills =

32

96

= 3 units / minute.

Let the time for which B is opened is x minutes.

According to the question, 4 × 18 + 3 × x = 96

3x = 96 - 72 = ⇒ 3x = 24

x = 8 minutes.

The pipe B should be closed after 8 minutes.

Answered by pv057966
3

Step-by-step explanation:

Let the total capacity of the tank be 96 units (LCM of 24 & 32).

A fills =

24

96

= 4 units / minute.

B fills =

32

96

= 3 units / minute.

Let the time for which B is opened is x minutes.

According to the question, 4 × 18 + 3 × x = 96

3x = 96 - 72 = ⇒ 3x = 24

x = 8 minutes.

The pipe B should be closed after 8 minutes.

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