Question

Pipe M and N running together can fill a cistern in 6 minutes. If M takes 5 minutes less than N to fill the cistern, then the time in which N alone can fill the cistern will be ?​

Answer 1

Answer:

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Step-by-step explanation:

=> Let pipe M fills the cistern in x minutes.

Therefore,

=> pipe N will fill the cistern in (x+5) minutes.

=> Now, 1/x + 1/(x+5) = 1/6 →

x = 10

Thus,

=> the pipe M can fill in 10 minutes, so N can fill in 10+5 =15 minutes.

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Answer 2

Answer:

SolutionLet the volume of cistern = V litre (L)

let the flow rate of one pipe be x L/min and that of other pipe be y L/min

Since 6 minute are needed to fill the pipe

6x+6y = V = total volume (1)

V/x = time taken by one pipe and V/y = time taken by other pipe

V/x + V/y = 5 min

1/x - 1/y = 5/V (2)