Question

pipe p and pipe q can empty a tank in one hour and one and half hour respectively pipes and pipe s can fill a tank two hours and two and half hours respectively the tank is filled to its capacity of fifteen litres and all four pipes opened simultaneously how much water remains in the tank after one hour​

Answer 1

Answer:

12 hours

Step-by-step explanation:

Part of the tank filled when all the three pipes are opened for 10 hours

=10×(

15

1

+

20

1

−

25

1

)=10×(

300

20+15−12

)=

300

230

=

30

23

Remaining empty part = 1−

30

23

=

30

7

Part of the tank filled in 1 hour by pipes (A and B) =

15

1

+

20

1

=

60

4+3

=

60

7

∵

60

7

part is filled in 1 hour

30

7

part is filled in 2 hours

∴ Total time to fill the tank =10+2=12 hours

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