Question

PipeA and B can fill the tank in 6 minute and 7 minute respectively. Starting from tap A each taps

are opened alternate for 1-1 min. In how much time the tank will be filled?​

Answer 1

Answer:

Step-by-step explanation:

Let the volume of cistern = LCM(6,7) = 42 litres

Tap A fills 7 litres in 1 minute.

Tap B fills 6 litres in 1 minute.

If they are opened alternately, they will fill 13 litres in 2 minutes.

This cycle will repeat [42/13] = 3 times taking 6 minutes filling 39 litres.

Remaining 3 litres will be filled by Tap A in 3/7 minutes.

Total time = 6 + 3/7 = 6 3/7 minutes

:-).

Hope it helps.