Math, asked by schoolclean8453, 11 months ago

Pipes A and B can fill a tank in 1 hour and 30 minutes respectively. Pipe C can empty is in 45 minutes. If all the three pipes are opened together when the tank is empty, then the tank will be filled in how many minutes?

Answers

Answered by kswami848
2

Answer:

36

Step-by-step explanation:

here we assume that total volume of tank=v

so rate of pipe A =v/60(m^3/minute)

like this

rate of B=v/30

rate of C=v/45

now let us assume total time will taken after start=x

so now we have

x(v/60+v/30-v/45)=v

xv/36=v

so x=36 minutes.

Answered by Raghav1330
0

Given:

Pipes A, B, and C can fill the tank in 1 hour, 30 minutes, and 45 minutes respectively.

To Find:

The time it will take to fill an empty tank if all three pipes are opened at the same time.

Solution:

Let the volume of the tank be x.

Let the Rate of pipe A be x/60.

Let the Rate of pipe B be x/30.

Let the Rate of pipe C be x/45.

Now, let's assume the total time taken by all the three pipes be y

   ⇒ y(\frac{x}{60} + \frac{x}{30} -  \frac{x}{45}) = x

   ⇒ x = 36 minutes

Therefore, it will take 36 minutes to fill the tank when all three pipes are opened at the same time.

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