Question

Pipes A and B can fill a tank in 1 hour and 30 minutes respectively. Pipe C can empty is in 45 minutes. If all the three pipes are opened together when the tank is empty, then the tank will be filled in how many minutes?

Answer 1

Answer:

36

Step-by-step explanation:

here we assume that total volume of tank=v

so rate of pipe A =v/60(m^3/minute)

like this

rate of B=v/30

rate of C=v/45

now let us assume total time will taken after start=x

so now we have

x(v/60+v/30-v/45)=v

xv/36=v

so x=36 minutes.

Answer 2

Given:

Pipes A, B, and C can fill the tank in 1 hour, 30 minutes, and 45 minutes respectively.

To Find:

The time it will take to fill an empty tank if all three pipes are opened at the same time.

Solution:

Let the volume of the tank be x.

Let the Rate of pipe A be x/60.

Let the Rate of pipe B be x/30.

Let the Rate of pipe C be x/45.

Now, let's assume the total time taken by all the three pipes be y

   ⇒ y($\frac{x}{60} + \frac{x}{30} - \frac{x}{45}$) = x

   ⇒ x = 36 minutes

Therefore, it will take 36 minutes to fill the tank when all three pipes are opened at the same time.