Question

pipes a and b can fill a tank in 5 and 6 hours respectively pipe c can empty it in 12 hour the tank is half full all the three pipes are in operation simultaneously after how much time will the tank will be full​

Answer 1

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I am using LCM method to solve this problem,

      A --- 5

      B --- 6          

      C --- -12

for total Capacity, take the LCM of 5,6,12 that is 60

Now per hour capacity of A= 60/5 = 12

      per hour capacity of B= 60/6 = 10

      per hour capacity of A= 60/-12 = -5

thus per hour capacity of A+B+C = 12+10-5 = 17

thus total time = total capacity/ per hour capacity = 60/17 hours

Step-by-step explanation: