Question

Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:

Answer 1

time taken by A to fill the tank=5hours
A's on hour work=1\5
time taken by B to fill the tank=6hours
B's one hour work=1/6
time taken by A and B to fill the tank=1/5+1\6
                                                     =11/30
time taken by C to empty the tank=12hours
C's one hour work=1\12
                         =11\30--1/12
                         =17/60
                         =60/17
                         =3whole9/17

Answer 2

$\huge{\mathfrak{\underline{Answer :}}} \\ \\ \underline{\boxed{\sf{Required \: time = 3\dfrac{9}{17}}}} \\ \\ \sf \huge{\mathfrak{\underline{Step-by-Step \: Explanation :}}} \\ \\ \textsf{Pipes A and B can fill the tank in 5 and 6 hours respectively.} \\ \\ \sf Therefore, \\ \textsf{Part filled by pipe A in 1 hour} = \sf \frac{1}{5} \\ \textsf{Part filled by pipe B in 1 hour} = \sf \frac{1}{6} \\ \\ \textsf{Pipe C can empty the tank in 12 hours.} \\ \sf Therefore, \\ \\ \textsf{Part emptied by pipe C in 1 hour} = \sf \frac{1}{12} \\ \\ \textsf{Net part filled by Pipes A, B, C together in 1 hour} \\ \qquad \sf \implies \frac{1}{5} + \frac{1}{6} - \frac{1}{12} \\ \qquad \sf \implies \frac{17}{60} \\ \\ \textsf{The tank can be filled in} \\ \qquad \sf \implies \frac{60}{17} \\ \qquad \sf \implies 3\frac{9}{17}$