Question

pipes a and b can fill tank in 5 and 6 hours respectively pipe C can empty in 12 hours the tank is half full of the three pipes are in Operation after how much time will the tank will be full​

Answer 1

f(x) = (2x3 – 5x2 + 9x – 8)

Now, x – 3 = 0  ⇒ x = 3

By the remainder theorem, we know that when f(x) is divided by (x – 3) the remainder is f(3).

Now, f(3) = 2 × 33 – 5 × 32 + 9 × 3 – 8

= 54 – 45 + 27 – 8

= 81 – 53 = 28

∴ The required remainder is 28.