Math, asked by riddhisinha, 10 months ago

piyush and ajittogether can complete a work in 3 days .they started together but after two days 2days ajit left the work . if the work is completed after 2 more days , piyush alone can complete it in how many days.

Answers

Answered by harpreet2223
49

1st Method:

(A+B)'s one day's work = 1/3 part;

(A+B) works 2 days together = 2/3 part;

Remaining work = 1-(2/3) = 1/3 part;

1/3 part of work is completed by A in two days;

Hence, one day's work of A = 1/6;

Then, one day's work of B = 1/3-1/6=1/6;

So, B alone can complete the whole work in 6 days.

2nd method:

(A+B)'s one day's % work = 100/3 = 33.3%

Work completed in 2 days = 66.6%

Remaining work = 33.4%;

One day's % work of A = 33.4/2 = 16.7%;

One day's work of B = 33.3 - 16.7 = 16.7%;

B alone can complete the work in,

= 100/16.7 = 6 days.

Answered by manushri81
29

Answer:

Piyush and Ajit takes 3 days to complete a work.

Their 2 day work= 1/3×2=2/3

Remaining work = 1-2/3 =1/3

Atq

1/3 of the work was done by Piyush in 2 days.

Therefore, the work was completed in :

(2)/1/3= 6 days

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