Physics, asked by ahrkproductions, 1 year ago

Pl answer this physics problem. I will mark you as BRAINLIEST.

The vernier calliper has 10 divisions and they are equal to 9 divisions of main scale length. If the main scale is calibrated in mm. What is its least count?

Answers

Answered by ananyareso
1

Answer:

0.1mm

Explanation:

Vernier Calliper is an instrument used to measure the internal and external diametres of small tubes .

The least count is the finest measurement you can take with the help of that vernier calliper.

So, Least Count =1MSD-1VSD

Here, 10 VSD=9MSD

therefore , 1VSD=9/10 MSD=0.9MSD

From above , Least Count =1MSD-1VSD

=1MSD-0.9MSD ( taking 1VSD=0.9MSD)

=0.1MSD =0.1mm

So, Least Count =0.1mm

please mark me as Brainliest answer!!

Similar questions