Pl answer this physics problem. I will mark you as BRAINLIEST.
The vernier calliper has 10 divisions and they are equal to 9 divisions of main scale length. If the main scale is calibrated in mm. What is its least count?
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Answer:
0.1mm
Explanation:
Vernier Calliper is an instrument used to measure the internal and external diametres of small tubes .
The least count is the finest measurement you can take with the help of that vernier calliper.
So, Least Count =1MSD-1VSD
Here, 10 VSD=9MSD
therefore , 1VSD=9/10 MSD=0.9MSD
From above , Least Count =1MSD-1VSD
=1MSD-0.9MSD ( taking 1VSD=0.9MSD)
=0.1MSD =0.1mm
So, Least Count =0.1mm
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