Question

PL please give the answer it is very urgent and I will mark best
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Answer 1

Answer:

In the given question, it is given that P and Q divide BA and CD respectively in the ratio 2:5. So,

AP=DQ=5x

PB=QC=2x

Now, using the formula;

Area of parallelogram=base×height

In parallelogram APDQ;

Ar(APDQ) = (5x)(h) ...(1)

Also,

In parallelogram PBCQ;

Ar(PBCQ) = (2x)(h) ...(2)

Dividing equation (1) by (2), we get

Ar(APDQ)Ar(PBCQ)=(5x)(h)(2x)(h)Ar(APDQ)Ar(PBCQ)=52Ar(APDQ)=52(Ar(PBCQ))

Therefore, Ar(APQD)=52(Ar(PBCQ))

Answer 2

Answer:

the given question, it is given that P and Q divide BA and CD respectively in the ratio 2:5. So,

AP=DQ=5x

PB=QC=2x

Now, using the formula;

Area of parallelogram=base×height

In parallelogram APDQ;

Ar(APDQ) = (5x)(h) ...(1)

Also,

In parallelogram PBCQ;

Ar(PBCQ) = (2x)(h) ...(2)

Dividing equation (1) by (2), we get

Ar(APDQ)Ar(PBCQ)=(5x)(h)(2x)(h)Ar(APDQ)Ar(PBCQ)=52Ar(APDQ)=52(Ar(PBCQ))

Therefore, Ar(APQD)=52(Ar(PBCQ))